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author | Jakob Unterwurzacher | 2017-08-02 23:34:14 +0200 |
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committer | Jakob Unterwurzacher | 2017-08-02 23:41:20 +0200 |
commit | e4fdb424964599db2e8d0ab273b6be804c6c9c12 (patch) | |
tree | 358e489ce40a86cfe5963d6f303d859396947d11 /build.bash | |
parent | 1f39ede4b46ec3609ccbe1d54402f4a17f3d697e (diff) |
build.bash: implement "you need Go 1.5" lockout in pure Go
As noticed by @riking, the logic in the bash script will break
when Go 1 version numbers reach double-digits.
Instead, use a build tag "!go1.5" to cause a syntax error:
$ /opt/go1.4.3/bin/go build
can't load package: package github.com/rfjakob/gocryptfs:
go1.4.go:5:1: expected 'package', found 'STRING' "You need Go 1.5 or higher to compile gocryptfs!"
Fixes https://github.com/rfjakob/gocryptfs/issues/133
Diffstat (limited to 'build.bash')
-rwxr-xr-x | build.bash | 10 |
1 files changed, 0 insertions, 10 deletions
@@ -30,16 +30,6 @@ BUILDTIME=$(date +%s) # Make sure we have the go binary go version > /dev/null -# Parse "go version go1.6.2 linux/amd64" to "1.6" -V=$(go version | cut -d" " -f3 | cut -c3-5) -# Reject old Go versions already here. It would fail with compile -# errors anyway. -if [[ $V == "1.3" || $V == "1.4" ]] ; then - echo "Error: you need Go 1.5 or higher to compile gocryptfs" - echo -n "You have: " - go version -fi - LDFLAGS="-X main.GitVersion=$GITVERSION -X main.GitVersionFuse=$GITVERSIONFUSE -X main.BuildTime=$BUILDTIME" go build "-ldflags=$LDFLAGS" $@ |