fsck: don't print corse corruption offset

The exact ciphertext block number (4KiB granularity) is
already printed in the doRead message. Don't cause
confusion by printing the 128KiB-granularity offset as
well.

  doRead 767: corrupt block #4: stupidgcm: message authentication failed
  fsck: error reading file "pa/d7/d14/f10c" (inum 767): 5=input/output error

1 files changed, 1 insertions, 1 deletions

diff --git a/fsck.go b/fsck.go
index e6a695a..fb9258c 100644
--- a/fsck.go
+++ b/fsck.go
@@ -128,7 +128,7 @@ func (ck *fsckObj) file(path string) {
 		result, status := f.Read(buf, off)
 		if !status.Ok() {
 			ck.markCorrupt(path)
-			fmt.Printf("fsck: error reading file %q (inum %d) at offset %d: %v\n", path, inum(f), off, status)
+			fmt.Printf("fsck: error reading file %q (inum %d): %v\n", path, inum(f), status)
 			return
 		}
 		// EOF